取一付扑克牌中的A、2、3、4、5和6，共24张，面朝上放在桌面上。现在有你和另外一个绝顶聪明的人来玩这个游戏。规则如下：从你开始，每次轮流将一张面朝上的牌合上，这张牌的点数累计到共同的点池中，A算1点；点池最先为0，谁先让点池里的点数超过31谁就输了。你该采取何种策略来让你自己能赢呢？

 

The Thirty-one Game. From a deck of cards, take the Ace, 2, 3, 4, 5, and 6 of each suit. These 24 cards are laid out face up on a table. The players alternate turning over cards and the sum of the turned over cards is computed as play progresses. Each Ace counts as one. The player who first makes the sum go above 31 loses. There is a catch. No integer may be chosen more than four times. The first player can win with optimal play. How?